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Topic: Dynamic application of several polynomials
Replies: 1   Last Post: Mar 16, 2013 3:14 AM

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 Bob Hanlon Posts: 906 Registered: 10/29/11
Re: Dynamic application of several polynomials
Posted: Mar 16, 2013 3:14 AM
 Plain Text Reply

x = Range[27000]/27001.;
f = {25.62, -38.43, 21.81}/9;

Clear[y];
y = (f.#^{3, 2, 1} &) /@ x;
ListLinePlot[y]

polynomials =
Map[{9 - #[[1]] - #[[2]], #[[1]], #[[2]]} &,
Flatten[Outer[
List, -{23.75, 28.02, 32.29, 36.56, 40.83, 45.1, 49.37, 53.64,
57.91, 62.18}, {13.48, 15.9, 18.33, 20.75, 23.17, 25.6, 28.02,
30.44, 32.87, 35.29}], 1]]/9;

Clear[y];
y[f_] := (f.#^{3, 2, 1} &) /@ x;

ListLinePlot[Evaluate[y /@ polynomials],
Frame -> True, Axes -> False,
ImageSize -> 500]

Bob Hanlon

On Fri, Mar 15, 2013 at 1:48 AM, Samuel <samuelsiqueira@gmail.com> wrote:
> I know how to get the 'resulting image' (y) from the application of a certain function (f) (here represented as the coefficients of a polynomial) over a certain interval (x):
>
> x = Range[27000]/27001.;
> f = {25.62, -38.43, 21.81}/9;
> y = Map[f[[1]]*#^3 + f[[2]]*#^2 + f[[3]]*# &, x];
> ListPlot[y]
>
> How do i get the 'resulting images' from the application of several polynomials (represented as its coefficients) over a certain interval (x)?
>
> Considering the representation of those several polynomials to be something like:
>
> polynomials = Map[{9 - #[[1]] - #[[2]], #[[1]], #[[2]]} &, Flatten[Outer[List, -{23.75, 28.02, 32.29, 36.56, 40.83, 45.1, 49.37, 53.64, 57.91, 62.18}, {13.48, 15.9, 18.33, 20.75, 23.17, 25.6, 28.02, 30.44, 32.87, 35.29}], 1]]/9;
>

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