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DOPPLER EFFECT MEANS VARIABLE SPEED OF LIGHT
Posted:
Mar 18, 2013 1:42 PM


http://www.cmmp.ucl.ac.uk/~ahh/teaching/1B24n/lect19.pdf Tony Harker, University College London: "The Doppler Effect: Moving sources and receivers. The phenomena which occur when a source of sound is in motion are well known. The example which is usually cited is the change in pitch of the engine of a moving vehicle as it approaches. In our treatment we shall not specify the type of wave motion involved, and our results will be applicable to sound or to light. (...) Now suppose that the observer is moving with a velocity Vo away from the source. (...) If the observer moves with a speed Vo away from the source (...), then in a time t the number of waves which reach the observer are those in a distance (cVo)t, so the number of waves observed is (cVo)t/lambda, giving an observed frequency f'=f(1Vo/c) when the observer is moving away from the source at a speed Vo."
Since, in a time t, "the number of waves observed is (cVo)t/lambda", the speed of the waves relative to the observer is c'=((cVo)t/lambda)(lambda/t)=cVo, in violation of special relativity.
http://physics.bu.edu/~redner/211sp06/class19/class19_doppler.html Sidney Redner: "The Doppler effect is the shift in frequency of a wave that occurs when the wave source, or the detector of the wave, is moving. Applications of the Doppler effect range from medical tests using ultrasound to radar detectors and astronomy (with electromagnetic waves). (...) We will focus on sound waves in describing the Doppler effect, but it works for other waves too. (...) Let's say you, the observer, now move toward the source with velocity vO. You encounter more waves per unit time than you did before. Relative to you, the waves travel at a higher speed: v'=v+vO. The frequency of the waves you detect is higher, and is given by: f'=v'/(lambda)=(v+vO)/(lambda)."
http://www.usna.edu/Users/physics/mungan/Scholarship/DopplerEffect.pdf Carl Mungan: "Consider the case where the observer moves toward the source. In this case, the observer is rushing headlong into the wavefronts, so that we expect v'>v. In fact, the wave speed is simply increased by the observer speed, as we can see by jumping into the observer's frame of reference. Thus, v'=v+v_o=v(1+v_o/v). Finally, the frequency must increase by exactly the same factor as the wave speed increased, in order to ensure that L'=L > v'/f'=v/f. Putting everything together, we thus have: OBSERVER MOVING TOWARD SOURCE: L'=L; f'=f(1+v_o/v); v'=v+v_o."
http://rockpile.phys.virginia.edu/mod04/mod34.pdf Paul Fendley: "Now let's see what this does to the frequency of the light. We know that even without special relativity, observers moving at different velocities measure different frequencies. (This is the reason the pitch of an ambulance changes as it passes you it doesn't change if you're on the ambulance). This is called the Doppler shift, and for small relative velocity v it is easy to show that the frequency shifts from f to f(1+v/c) (it goes up heading toward you, down away from you). There are relativistic corrections, but these are negligible here."
It is explicit in Sidney Redner's and Carl Mungan's texts and implicit in Paul Fendley's text that the frequency shift from f to f'=f(1+v/c) can only be caused by a shift in the speed of light (relative to the observer) from c to c'=c+v, in violation of special relativity.
See more here:
http://fqxi.org/data/essaycontestfiles/Valev_Shift_in_Frequency_Im.pdf Shift in Frequency Implies Shift in Speed of Light
Pentcho Valev



