
Re: Half Measure and Correction
Posted:
Mar 24, 2013 1:37 PM


On Mar 24, 10:53 am, David C. Ullrich <ullr...@math.okstate.edu> wrote: > [. . .] > So the more interesting version of the question, > in any case less trivial, amounts to this: Is there > a measurable set D such that > > 0 < m(D intersect I) < m(I) > > for every open interval I,
Didn't we just have that thread?
http://groups.google.com/group/sci.math/msg/0cfe35786f2279f0?hl=en
> and such that m(D intersect [0,1]) = 1/2 ?
OK, that's different.
> The answer is yes, by the way. Think about > "fat Cantor sets". Start with a Cantor set, then > add some more Cantor sets, one in each interval > the first set misses. Repeat until done...

