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Topic: Transitive Closure Proof
Replies: 5   Last Post: Mar 25, 2013 11:17 AM

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Ara M Jamboulian

Posts: 65
Registered: 12/6/04
Re: Transitive Closure Proof
Posted: Mar 25, 2013 4:47 AM
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Yes it is, but needs proof

Suppose
(x,y,z) ~ (a,b,c)
and
(a,b,c) ~ (r,s,t)

This means
xa + yb = 0 or bx - ay = 0 i.e. y/x = -a/b or y/x = b/a
and
ar + bs = 0 or sa - rb = 0 i.e. b/a = -r/s or b/a = s/r

There are four cases to consider



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