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dpb
Posts:
8,369
Registered:
6/7/07


Re: Removing a location from a vector.
Posted:
Mar 25, 2013 3:54 PM


On 3/24/2013 3:50 PM, Skylar wrote: ... With that you can then find which are true collectively by simply writing the expression
ixAll = all([ixPr ixT ixDT],2);
which will be a logical (column) vector of the same length but T only where each of the three conditions you've tested for is simultaneously T.
Again, not sure where you're headed, but hopefully that gives some ideas. Note that to get the values you then simply can write expressions like
S=suture2(ixAll,:);
to get the full dataset (all columns) for the rows found.
Or, of course, if this is an exclusion process, then perhaps you're looking for
suture2(ixAll,:)=[];
to collapse to everything except those found above...
Salt to suit, obviously.




