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Re:  conjecture on a diophantine equation
Posted:
Mar 26, 2013 12:47 AM


On Sun, 24 Mar 2013, Deep wrote:
Don't use  three times, once is more than enough.
> Consider the following equation under the given conditions. > > x^2k + y^2k = z^2k (1) > > Conditions: x, z are coprime odd integers, prime k > 3 > Conjecture: y^k = U^(1/2) where U is a nonsquare integer.
False. x = z = 1; y = 0



