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Topic: matrix differentials
Replies: 3   Last Post: Apr 4, 2013 2:28 PM

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Posts: 1
Registered: 3/27/13
Re: matrix differentials
Posted: Mar 27, 2013 6:38 AM
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transpose is a linear operator, so d(P')=d(P)'.

d(P')*V*P=d(P)'*V*P is a scale,
so d(P)'*V*P = (d(P)'*V*P)' = P'*V'*d(P)

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