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Topic: Integral calculation!
Replies: 4   Last Post: Mar 30, 2013 12:37 PM

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Jose Carlos Santos

Posts: 4,896
Registered: 12/4/04
Re: Integral calculation!
Posted: Mar 30, 2013 10:22 AM
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On 30-03-2013 10:11, Roland Franzius wrote:

>> I need to calculate integral(0,pi/4) x.tan x dx.

> int dx x tan x = x^2 tan x - int dx x^2/(1+x^2)=


> x^2 tan x - int dx ( 1 - 1/(1+x^2) )

Best regards,

Jose Carlos Santos

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