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Topic: Integral calculation!
Replies: 4   Last Post: Mar 30, 2013 12:37 PM

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karl

Posts: 397
Registered: 8/11/06
Re: Integral calculation!
Posted: Mar 30, 2013 12:37 PM
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Am 30.03.2013 15:35, schrieb Roland Franzius:
> Am 30.03.2013 15:22, schrieb José Carlos Santos:
>> On 30-03-2013 10:11, Roland Franzius wrote:
>>

>>>> I need to calculate integral(0,pi/4) x.tan x dx.
>>>>
>>>> http://at.yorku.ca/cgi-bin/bbqa?forum=calculus;task=list

>>>
>>> int dx x tan x = x^2 tan x - int dx x^2/(1+x^2)=

>>
>> Wrong!
>>

>>> x^2 tan x - int dx ( 1 - 1/(1+x^2) )
>>
>>
>> Best regards,
>>
>> Jose Carlos Santos
>>

>
> 1 credit point!
>


Oh, he did it again!!!
:-((



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