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Topic:
Misner, Thorne and Wheeler, Exercise 8.5 (c)
Replies:
38
Last Post:
Apr 13, 2013 11:57 PM




Re: Misner, Thorne and Wheeler, Exercise 8.5 (c)
Posted:
Apr 8, 2013 9:08 PM


> which again with [1] gives > r r''' + 3 r'' r' = 0 > > So if you find some r(t) that has r''(t) = r'''(t) = 0 for all t, > you're done. Easy. Take > r(t) = A t + B [3]
Yes, thats a "trivial" solution and as you hinted, there are others. The general solution to this is r = s(At2 + Bt + C), which can be ~ at + b if its a perfect square.
I do like Alfred's elegant approach!


Date

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4/7/13


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4/7/13


Lord Androcles, Zeroth Earl of Medway

4/8/13


Lord Androcles, Zeroth Earl of Medway

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4/8/13


Lord Androcles, Zeroth Earl of Medway

4/8/13


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4/9/13


Lord Androcles, Zeroth Earl of Medway

4/9/13


Hetware

4/8/13


Hetware

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Lord Androcles, Zeroth Earl of Medway

4/9/13


Hetware

4/9/13


Lord Androcles, Zeroth Earl of Medway

4/9/13


Hetware

4/9/13


Lord Androcles, Zeroth Earl of Medway

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Dirk Van de moortel

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Lord Androcles, Zeroth Earl of Medway

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rotchm@gmail.com

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Dirk Van de moortel

4/13/13


Dono

4/13/13


rotchm@gmail.com

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Dono

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Dono

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Dono

4/13/13


rotchm@gmail.com

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Dono

4/13/13


rotchm@gmail.com

4/13/13


Dono

4/13/13


Dono

4/13/13


rotchm@gmail.com

4/13/13


Dono

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rotchm@gmail.com

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Dono

4/9/13


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Dirk Van de moortel

4/9/13


Lord Androcles, Zeroth Earl of Medway

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Lord Androcles, Zeroth Earl of Medway


