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Topic: Misner, Thorne and Wheeler, Exercise 8.5 (c)
Replies: 38   Last Post: Apr 13, 2013 11:57 PM

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 rotchm@gmail.com Posts: 58 Registered: 5/27/07
Re: Misner, Thorne and Wheeler, Exercise 8.5 (c)
Posted: Apr 13, 2013 7:59 PM

On Apr 13, 7:12 pm, "Dono." <sa...@comcast.net> wrote:

> > r = s(At2 + Bt  + C), which can be ~ at + b if its a perfect square.
>
> You mean r=\sqrt(At^2+Bt+C), arithmetic ignoramus.

Smart people knew what it meant. DvDM knew it. You read his post and
still failed to understand the notation. The I explicited it to you
and yo STILL failed to understand it.

> A, B and C aren't arbitrary, they are tied to each other through some
> constants of integration, c1=r(0), c2=r'(0) and c3=r"(0),

Well DuH... tell me something I dont know!

You are again trying to hide your failures....