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Topic: Misner, Thorne and Wheeler, Exercise 8.5 (c)
Replies: 38   Last Post: Apr 13, 2013 11:57 PM

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 Dono Posts: 368 Registered: 11/6/06
Re: Misner, Thorne and Wheeler, Exercise 8.5 (c)
Posted: Apr 13, 2013 8:03 PM

On Apr 13, 4:59 pm, rotchm <rot...@gmail.com> wrote:
> On Apr 13, 7:12 pm, "Dono." <sa...@comcast.net> wrote:
>

> > > r = s(At2 + Bt  + C), which can be ~ at + b if its a perfect square.
>
> > You mean r=\sqrt(At^2+Bt+C), arithmetic ignoramus.
>
> Smart people knew what it meant.

Only an imbecile like you would write s(At2 + Bt + C). You are
obviously ignorant of the very basics of mathematical notation,
pretender.

> The I explicited it to you
> and yo STILL failed to understand it.
>

You didn't liar.

> >  A, B and C aren't arbitrary, they are tied to each other through some
> > constants of integration, c1=r(0), c2=r'(0) and c3=r"(0),

>
> Well DuH... tell me  something I dont know!
>

You obviously don't, since you wrote A,B and C.