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Topic: Misner, Thorne and Wheeler, Exercise 8.5 (c)
Replies: 38   Last Post: Apr 13, 2013 11:57 PM

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 Dono Posts: 368 Registered: 11/6/06
Re: Misner, Thorne and Wheeler, Exercise 8.5 (c)
Posted: Apr 13, 2013 8:08 PM

On Apr 13, 4:59 pm, rotchm <rot...@gmail.com> wrote:
> On Apr 13, 7:12 pm, "Dono." <sa...@comcast.net> wrote:
>

> > > r = s(At2 + Bt  + C), which can be ~ at + b if its a perfect square.
>
> > You mean r=\sqrt(At^2+Bt+C), arithmetic ignoramus.
>
> The I explicited it to you and yo STILL failed to understand it.

You are not only an imbecile, you are also a liar, here is what you
wrote:

>
> >  A, B and C aren't arbitrary, they are tied to each other through some
> > constants of integration, c1=r(0), c2=r'(0) and c3=r"(0),

>
> Well DuH... tell me  something I dont know!
>

OK, let's try a simple test, what is the expression for A?