In article <firstname.lastname@example.org>, WM <email@example.com> wrote:
> On 17 Apr., 21:41, Virgil <vir...@ligriv.com> wrote: > > > > A rhetorical question. Even Virgil knows that the answer is "no". > > > > Is there a line containing EVERY member of A? > > Yes, of course.
Which line would that be? > > > Is there for every line a member of A not in that line? > > Of course. > > If A was actually infinite, then it should be larger than all lines of > B. This could only be proven by an element of A that is not in B.
Since B is actually infinite also, why cannot A and B biject, with each member of A pairing off with the FISON in B of which it is that largest member?
The point here is that A has members which are not members of B and vice versa, so neither can be subset of the other. Similarly nether can be a member of the other.
> But here we do > mathematics.
What WM does, particularly when in Wolkenmuekenheim, is mere WMytheology, not even close to being mathematics. --