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Brentt
Posts:
60
Registered:
9/24/11


Re: Mathematica integration Vs Sympy
Posted:
Apr 21, 2013 5:18 AM


The result:
In[0]: Integrate[1/(x*(1  a*(1  x))), x] Out[0]: (Log[1 + a (1 + x)]  Log[x])/(1 + a)
Seems to be true for all complex a and x . Why do you think it assumes a>1?
On Sat, Apr 20, 2013 at 2:42 AM, Sergio R <sergiorquestion@gmail.com> wrote:
> Hello all, > > Just for fun a put an integral I was doing via mathematica > WolframAlpha > [ > http://www.wolframalpha.com/input/?i=Integrate[1%2F%28x*%281a*%281x%29%29%29%2Cx] > ] > into the online sympy [ http://live.sympy.org/ ] console > the following: > > a = Symbol('a'); g = 1/(x*(1a*(1x))) ; u=simplify(integrate(g,x)) > > Then, to display the result, at the sympy ">>>" prompt, type u > and hit return. > > To my surprise, sympy seems to give the right result without any > assumption, while mathematica's result seems to assume a>1, which is > not specified. Also for this case (a>1) sympy gives an extra constant > which is not present in the mathematica result. > > Is there a way to make mathematica to output a general result like > sympy > in this case? > > Sergio > >



