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Topic: Sparse Array Question
Replies: 2   Last Post: Apr 24, 2013 7:02 AM

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Sseziwa Mukasa

Posts: 106
Registered: 8/26/07
Re: Sparse Array Question
Posted: Apr 24, 2013 7:02 AM
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One idea:

#[[1, 1]] -> Total[#[[All, 2]]] & /@ Split[Sort[myList], #[[1]] == #2[[1]] &]

In versions 7 and later you can do:

#[[1, 1]] -> Total[#[[All, 2]]] & /@ GatherBy[myList, #[[1]] &]

On Apr 23, 2013, at 12:04 AM, christopher arthur <chris.arthur1@gmail.com> wrote:

> Hello,
>
> I have a list of rules for defining a SparseArray. The list has some
> coordinates repeated with different values. If a coordinate appears in
> the list more than once, I want to sum up the values, and then have a
> SparseArray
>
> i.e., if my list were myList={{1,1}->1,{2,1}->2,{1,1}->3} then my
> SparseArray should have {1,1}->4. I've tried using ReplacePart on an
> array to say myArray=ReplacePart[myArray,...] but this seems horribly
> inefficient as a way to change values in an array.
>
> I'm using Mathematica 5.2
>
> Cheers,
>
> Chris
>






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