The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » sci.math.* » sci.math

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: The formula for the inner angles of a polygon with 99 vertices?
Replies: 10   Last Post: May 2, 2013 9:24 AM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]

Posts: 1,448
Registered: 4/7/12
Re: The formula for the inner angles of a polygon with 99 vertices?
Posted: May 1, 2013 6:18 PM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

On 2 Maj, 00:06, JT <> wrote:
> On 1 Maj, 23:56, 1treePetrifiedForestLane <>
> wrote:

> > tdhis is how the terminology arose,
> > There is no where, thereinsville.

> Or it could also be so simple that the angle of the 99 side polygon is
> 48,5/99 subturns.

> > > ((99/2)-1)/99)*360=176,3636363636364
> > > Isn't this formula easier then the one you use?
> Or why not just write

So the formula for a the inner angle of a regular polygon as expressed
in subturns, (maybe revolutions is better?) would be ((n/2)-1)/n

Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.