JT
Posts:
1,448
Registered:
4/7/12


Re: The formula for the inner angles of a polygon with 99 vertices?
Posted:
May 1, 2013 6:18 PM


On 2 Maj, 00:06, JT <jonas.thornv...@gmail.com> wrote: > On 1 Maj, 23:56, 1treePetrifiedForestLane <Space...@hotmail.com> > wrote: > > > tdhis is how the terminology arose, > > There is no where, thereinsville. > > Or it could also be so simple that the angle of the 99 side polygon is > 48,5/99 subturns. > > > > > > ((99/2)1)/99)*360=176,3636363636364 > > > > Isn't this formula easier then the one you use? > > Or why not just write
So the formula for a the inner angle of a regular polygon as expressed in subturns, (maybe revolutions is better?) would be ((n/2)1)/n

