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Topic: The formula for the inner angles of a polygon with 99 vertices?
Replies: 10   Last Post: May 2, 2013 9:24 AM

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 JT Posts: 1,448 Registered: 4/7/12
Re: The formula for the inner angles of a polygon with 99 vertices?
Posted: May 1, 2013 6:18 PM

On 2 Maj, 00:06, JT <jonas.thornv...@gmail.com> wrote:
> On 1 Maj, 23:56, 1treePetrifiedForestLane <Space...@hotmail.com>
> wrote:
>

> > tdhis is how the terminology arose,
> > There is no where, thereinsville.

>
> Or it could also be so simple that the angle of the 99 side polygon is
> 48,5/99 subturns.
>
>
>

> > > ((99/2)-1)/99)*360=176,3636363636364
>
> > > Isn't this formula easier then the one you use?
>
> Or why not just write

So the formula for a the inner angle of a regular polygon as expressed
in subturns, (maybe revolutions is better?) would be ((n/2)-1)/n

Date Subject Author
5/1/13 JT
5/1/13 Brian Q. Hutchings
5/1/13 JT
5/1/13 JT
5/1/13 JT
5/1/13 William Elliot
5/1/13 Wally W.
5/2/13 Robin Chapman
5/2/13 JT
5/2/13 JT
5/2/13 JT