
Re: N^N
Posted:
May 3, 2013 12:53 AM


On May 2, 9:59 pm, William Elliot <ma...@panix.com> wrote: > On Tue, 30 Apr 2013, Butch Malahide wrote: > > On Apr 29, 11:28 pm, Butch Malahide <fred.gal...@gmail.com> wrote: > > > On Apr 29, 9:17 pm, William Elliot <ma...@panix.com> wrote: > > > > > Why in N^N homeomorphic to R\Q? > > > > R\Q is homeomorphic to the space of *positive* irrational numbers. The > > > simple continued fraction expansion is a natural bijection between the > > > positive irrationals and the space N^N. > > > Where by "positive irrationals" I mean irrationals between 0 and 1. > > How so? The continued fraction for positive integers a1, a2,.. > [a1, a2,.. ] = a1 + 1/(a2 + 1/(a3 + ..)) > > Would not those continued fractions not be > limited to (0,1) but to (0,oo)?
By (0,oo) do you mean (1,oo)?

