
Re: The nature of gravity
Posted:
May 4, 2013 2:04 PM


It is not only the Planck units that are tied up with the proton. All timescale masses are. Take a look at our own SI system:
The GM product of our own SI system's timescale mass is 6.7360006x10^24. It has to be that in order to make its Schwarzschild diameter equal one light second.
As you will have gathered by now 29.6906036 is the GM product of the proton opposite. It has to be because its Schwarzschild diameter is equal to the proton Compton wavelength, 1.32141x10^15m.
6.7360006x10^24 divided by 29.6906036 is 2.2687314x10^23 which is the Compton frequency of the proton.
This means that the Timescale mass of any mass model where the metre and second are used can be divided up as follows:
29.6906036(2.2687314x10^23) or 29.6906036(4.763120196x10^11)^2. In the case of the protonic model the mass structure is equal to (29.6906036/G)^3, using local protonic G, 6.23343585x10^11. Because of this particular phenomenon we can construct the following formula to confirm local G:
2[{(29.6906036^3)/C}^0.5]/C=6.23343585x10^11.
As the SI system's kilogram is heavier than the protonic mass unit by a factor of (x) the timescale mass of our system must be nominally less than the protonic system's 1.080624035x10^35 units by the same factor of (x). This means that, although, the structure will start off as 29.6906036(4.763120196x10^11)^2 it will soon become clear that each component of 4.763120196x10^11 will be weighed in kilograms and will, therefore, be equal to (29.6906036)(x).
Using the same formula as above we will see that SI G will be (6.23343585x10^11)(x): {(29.6906036)^3}(x)^2} and so as above. This particular framework also becomes the quantum gravitational base of the gravitational field expressed in quantum units. Here's how:
(1). {(29.6906036)^3x)^2}{(C^2)/h}=(3.550112433x10^54)(x)^2.
(2). {3.550112433x10^54(x)^2}/G^3=1.369513x10^85=quantum gravitational field. Gravity is a surface phenomenon and therefore this result is two dimensional. The square root of 1.3569513x10^85 is 3.700693179x10^42 which is the Planck frequency. The gravitational equations we are used to seeing are three dimensionalised values adjusted from a two dimensional phenomenon. We can three dimensionalise our quantum gravitational field. It requires a few adjustments but not today.
(3) You might ask how I came to get to 1.369513x10^85 without the required SI G^3, see beginning of section (2) above. It was done like this: {(3.55011243x10^54(x)^2}/G^3. In place of G I substituted two known values of local G. One was the Protonic, 6.23343585x10^11 and the other was the Inbetweener, 6.44873x10^11, which can be found several ways, one is simply 30.716077/4.763210196x10^11. 3.55011243x10^54 was divided by 6.23343585x10^11 and the result divided by (6.44873x10^11)^2. It shouldn't take much analysis; we need to balance up the (x)^2 in 3.55011243x10^54(x)^2. Well, we know that protonic G is less than SI G by (x). And we know that Inbetweener G is less by (x)0.5. As we are using the square of the Inbetweener G we effectively adjust the equation by the required(x)^2.

