On 7 Maj, 04:18, donstockba...@hotmail.com wrote: > On Monday, May 6, 2013 9:03:27 PM UTC-5, JT wrote: > > Knowing that a hexagon built by isocles we can split them into right > > > triangles and have hy^2-0.5hy^2=b^2. > > > And from there we create a new dodecagon knowing the difference > > > between base and hypotenuse we can calculate required heights of new > > > vertices, we plug it in and get hypotenuse of triangle forming new > > > vertice. > > > We repeat all this splitting hexagon, dodecagon, 24, 48, 96, 192... > > > recursively until sought smoothness of the circle is aquired while > > > adding vertices and triangle areas. > > Only one calculation is needed if you just know pi.
Yes but Pi is approximation, my answer would be a fraction and therefor exact for the sought and aquired smoothness.