Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: FINAL SPECIFIC CALCULUS OF PRIME NUMBER AS SHOWN HERE POSTED WITH
CAMBRIDGE JOURNALS AND JOHN HOPKINS MATHEMATICS JOURNALS

Replies: 2   Last Post: May 7, 2013 11:27 PM

 Messages: [ Previous | Next ]
 Don Redmond Posts: 117 Registered: 5/5/11
Re: FINAL SPECIFIC CALCULUS OF PRIME NUMBER AS SHOWN HERE POSTED
WITH CAMBRIDGE JOURNALS AND JOHN HOPKINS MATHEMATICS JOURNALS

Posted: May 7, 2013 6:27 PM

On Tuesday, May 7, 2013 10:42:37 AM UTC-5, hope...@frontier.com wrote:
> This calculus is submitted to the best Mathematics brains in the World , Cambridge Journals , John Hopkins Journals, Its basic condition is mathematically solvable. Half-line value at 18 runs tandem with prime numbers thus allowing all calibrations. Please try and understand it first before blurting, as is the method of current mathematics, specially your Sci- math research. Prime number is only a created mystery , created by current mathematics, not a real mystery. It is obvious that we need a predictive calculus , which should be easy and many of you are chasllenged to the same
>
> .
>
> XYZ (3coordinates to the calculus)
>
> (Z>Y>X)>series progression
>
>
>
> Main Condition of the Calculus of Prime numbers, and the half- line 18
>
> (X*Y)+Y*[(Y+Z)-(X+Y)] =Y*Z
>
> The calculus is infinite Z>
>
>
>
> Examples:
>
>
>
> A. half-line values at 18(6*3) calculus. These values are at 29,31,47,53,61,71,79,101,157,173,191,193??..
>
>
>
> (29*31)+31*[(29+31)-(31+47)] = (31*47)
>
> (31*47)+47*[(47+53)-(47+31)] = (47*53)
>
> (47*53)+53*[(53+61)-(47+53)] = (53*61)
>
> (53*61)+61*[(71+61)-(53+61)] = (61*71) so on infinite
>
>
>
> B. General Prime numbers calculus:5,7,11,13,17,19,23,29,31,37,41,43,47???..
>
>
>
> Example starting at Prime number 19
>
> (19*13)+19*[(19+29)-(19+13)]=(19*29)
>
> 19*29+29*[(29+37)-(19+29)]=29*37
>
> (29*37)+37*[(37+43)-(29+37)]=(37*43)?.so on infinite
>
>
>
> Vinoo Cameron .

Cute.

Note that

7e + e[(e + pi) - (7 + e)] = e * pi,

where e is the base of the nat logs and pi is the circle constant. Any three
complex numbers will work for x, y and z. Algebraic identities are like that.

Don

Date Subject Author
5/7/13 HOPEINCHRIST
5/7/13 Don Redmond
5/7/13 trj