
Re: FINAL SPECIFIC CALCULUS OF PRIME NUMBER AS SHOWN HERE POSTED WITH CAMBRIDGE JOURNALS AND JOHN HOPKINS MATHEMATICS JOURNALS
Posted:
May 7, 2013 6:27 PM


On Tuesday, May 7, 2013 10:42:37 AM UTC5, hope...@frontier.com wrote: > This calculus is submitted to the best Mathematics brains in the World , Cambridge Journals , John Hopkins Journals, Its basic condition is mathematically solvable. Halfline value at 18 runs tandem with prime numbers thus allowing all calibrations. Please try and understand it first before blurting, as is the method of current mathematics, specially your Sci math research. Prime number is only a created mystery , created by current mathematics, not a real mystery. It is obvious that we need a predictive calculus , which should be easy and many of you are chasllenged to the same > > . > > XYZ (3coordinates to the calculus) > > (Z>Y>X)>series progression > > > > Main Condition of the Calculus of Prime numbers, and the half line 18 > > (X*Y)+Y*[(Y+Z)(X+Y)] =Y*Z > > The calculus is infinite Z> > > > > Examples: > > > > A. halfline values at 18(6*3) calculus. These values are at 29,31,47,53,61,71,79,101,157,173,191,193??.. > > > > (29*31)+31*[(29+31)(31+47)] = (31*47) > > (31*47)+47*[(47+53)(47+31)] = (47*53) > > (47*53)+53*[(53+61)(47+53)] = (53*61) > > (53*61)+61*[(71+61)(53+61)] = (61*71) so on infinite > > > > B. General Prime numbers calculus:5,7,11,13,17,19,23,29,31,37,41,43,47???.. > > > > Example starting at Prime number 19 > > (19*13)+19*[(19+29)(19+13)]=(19*29) > > 19*29+29*[(29+37)(19+29)]=29*37 > > (29*37)+37*[(37+43)(29+37)]=(37*43)?.so on infinite > > > > Vinoo Cameron .
Cute.
Note that
7e + e[(e + pi)  (7 + e)] = e * pi,
where e is the base of the nat logs and pi is the circle constant. Any three complex numbers will work for x, y and z. Algebraic identities are like that.
Don

