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Topic: Is it me or is it Wolfram?
Replies: 16   Last Post: May 13, 2013 4:51 PM

 Messages: [ Previous | Next ]
 JT Posts: 1,448 Registered: 4/7/12
Re: Is it me or is it Wolfram?
Posted: May 9, 2013 2:17 PM

On 9 Maj, 20:14, JT <jonas.thornv...@gmail.com> wrote:
> On 9 Maj, 20:01, JT <jonas.thornv...@gmail.com> wrote:
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> >http://www.wolframalpha.com/input/?i=0.499999999999999999999999999999...
>
> > n = -1.
> > 0.49999999999999999999999999999999999999999 = (n/2-1)/n

>
> >http://www.wolframalpha.com/input/?i=%3D%2810000000000000000000000000...
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> > 0.49999999999999999999999999999999999999999=(100000000000000000000000000000000000000000/2-1)/
> > 100000000000000000000000000000000000000000

>
> > I do not understand to, can please someone explain why and how wolfram
> > get -1 for the upper calculation, it is obvious using the one below
> > what the solution is?

>
> > And if there was two solutions should not Wolfram give them both? What
> > is going on here, i am total newb to math calculators so tell me what
> > is going on?

>
> It is apparently adding the 11th decimal digit something goes terribly
> wrong with wolfram alpha because it works perfectly well for.
> 0.4999999999 = (n/2-1)/nhttp://www.wolframalpha.com/input/?i=0.4999999999+%3D+%28n%2F2-1%29%2Fn

Is it an overflow?

Date Subject Author
5/9/13 JT
5/9/13 JT
5/9/13 JT
5/10/13 JT
5/10/13 JT
5/10/13 RGVickson@shaw.ca
5/10/13 JT
5/10/13 JT
5/10/13 JT
5/10/13 LudovicoVan
5/10/13 JT
5/10/13 LudovicoVan
5/10/13 JT
5/10/13 JT
5/12/13 JT
5/13/13 JT
5/13/13 Brian Q. Hutchings