On 9 Maj, 20:17, JT <jonas.thornv...@gmail.com> wrote: > On 9 Maj, 20:14, JT <jonas.thornv...@gmail.com> wrote: > > > > > > > > > > > On 9 Maj, 20:01, JT <jonas.thornv...@gmail.com> wrote: > > > >http://www.wolframalpha.com/input/?i=0.499999999999999999999999999999... > > > > n = -1. > > > 0.49999999999999999999999999999999999999999 = (n/2-1)/n > > > >http://www.wolframalpha.com/input/?i=%3D%2810000000000000000000000000... > > > > 0.49999999999999999999999999999999999999999=(100000000000000000000000000000000000000000/2-1)/ > > > 100000000000000000000000000000000000000000 > > > > I do not understand to, can please someone explain why and how wolfram > > > get -1 for the upper calculation, it is obvious using the one below > > > what the solution is? > > > > And if there was two solutions should not Wolfram give them both? What > > > is going on here, i am total newb to math calculators so tell me what > > > is going on? > > > It is apparently adding the 11th decimal digit something goes terribly > > wrong with wolfram alpha because it works perfectly well for. > > 0.4999999999 = (n/2-1)/nhttp://www.wolframalpha.com/input/?i=0.4999999999+%3D+%28n%2F2-1%29%2Fn > > Is it an overflow?
Really noone knows why this happen? This is not quantum mechanic, i would say it is an overflow in an operation am i right? But where does -1 come from?