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Topic: Is it me or is it Wolfram?
Replies: 16   Last Post: May 13, 2013 4:51 PM

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JT

Posts: 1,150
Registered: 4/7/12
Re: Is it me or is it Wolfram?
Posted: May 13, 2013 11:03 AM
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On 12 Maj, 10:28, JT <jonas.thornv...@gmail.com> wrote:
> On 10 Maj, 20:04, "Julio Di Egidio" <ju...@diegidio.name> wrote:
>
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> > "JT" <jonas.thornv...@gmail.com> wrote in message
>
> >news:82f721d1-c691-47fa-8428-913e49966f62@m7g2000vbf.googlegroups.com...
>
> > >http://www.wolframalpha.com/input/?i=0.499999999999999999999999999999...
>
> > > n = -1.
> > > 0.49999999999999999999999999999999999999999 = (n/2-1)/n

>
> > >http://www.wolframalpha.com/input/?i=%3D%2810000000000000000000000000...
>
> > > 0.49999999999999999999999999999999999999999=(100000000000000000000000000000 000000000000/2-1)/
> > > 100000000000000000000000000000000000000000

>
> > > I do not understand to, can please someone explain why and how wolfram
> > > get -1 for the upper calculation, it is obvious using the one below
> > > what the solution is?

>
> > > And if there was two solutions should not Wolfram give them both? What
> > > is going on here, i am total newb to math calculators so tell me what
> > > is going on?

>
> > Take the equation k = (n/2-1)/n, and consider that your k is not fitting
> > into a float (most probably they are using doubles, i.e. the 64-bit floats,
> > but I haven't checked), so k is (apparently) rounded to 0.5.  Then,
> > depending on how you transform the equation and the exact step at which you
> > substitute your value for k, you either get -Infinity or -1 (exercise left
> > to the reader, or I guess you could just check the step-by-step solution,
> > but I haven't).

>
> > That is how floating point works: you'd rather ideally use
> > arbitrary-precision rationals, otherwise, as mentioned already in the
> > thread, increase the precision of your floating point numbers.  But I do not
> > think you can do any of these with Wolfram Alpha.

>
> > Julio
>
> You are a fucking clueless monkey Julio, don't you think that
> mathematica can handle a simple division, together with Wofram,
> mathematica is one of the most__accurate__ math packages out there on
> the market. And they should not be able to handle simple floating
> point arithmetic that take 3 days to program. Even for me that do not
> even claim to be a competent programmer in any language i would do it
> in notime. So that is not why....... instead it is their arithmetic
> simply fucked up it, so no it isn't sound. They should build it upon
> geometrical principles known since Zohan of Babylon. The ones behind
> that programming is fucked up prostitutes to mainstream nillywilly
> anal imaginary half cats. This is what i think about them.
>
> http://www.dailymail.co.uk/news/article-2321146/What-earth-Half-cat-c...http://www.youtube.com/watch?v=1SkUxknvRlc
>
> http://www.youtube.com/watch?v=ndN_5IrPOhc
> Back in the day of Babylon the priest was astronoms, so the whole
> geometric priniciples was founded by priests. And the most famous of
> them all was Zohan, also known as Zoroaster. The village of Zohan can
> still be found in Iran. We often focus upon other traits of
> Zoroaster,
> that have become larger then life after his death myths, but during
> the time of Babylon he was the greatest astronom, mathematician the
> world had seen.


What is wrong with your aritmethic?



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