Search All of the Math Forum:
Views expressed in these public forums are not endorsed by
NCTM or The Math Forum.


Math Forum
»
Discussions
»
sci.math.*
»
sci.math
Notice: We are no longer accepting new posts, but the forums will continue to be readable.
Topic:
Is it me or is it Wolfram?
Replies:
16
Last Post:
May 13, 2013 4:51 PM



JT
Posts:
1,448
Registered:
4/7/12


Re: Is it me or is it Wolfram?
Posted:
May 13, 2013 11:03 AM


On 12 Maj, 10:28, JT <jonas.thornv...@gmail.com> wrote: > On 10 Maj, 20:04, "Julio Di Egidio" <ju...@diegidio.name> wrote: > > > > > > > > > > > "JT" <jonas.thornv...@gmail.com> wrote in message > > >news:82f721d1c69147fa8428913e49966f62@m7g2000vbf.googlegroups.com... > > > >http://www.wolframalpha.com/input/?i=0.499999999999999999999999999999... > > > > n = 1. > > > 0.49999999999999999999999999999999999999999 = (n/21)/n > > > >http://www.wolframalpha.com/input/?i=%3D%2810000000000000000000000000... > > > > 0.49999999999999999999999999999999999999999=(100000000000000000000000000000 000000000000/21)/ > > > 100000000000000000000000000000000000000000 > > > > I do not understand to, can please someone explain why and how wolfram > > > get 1 for the upper calculation, it is obvious using the one below > > > what the solution is? > > > > And if there was two solutions should not Wolfram give them both? What > > > is going on here, i am total newb to math calculators so tell me what > > > is going on? > > > Take the equation k = (n/21)/n, and consider that your k is not fitting > > into a float (most probably they are using doubles, i.e. the 64bit floats, > > but I haven't checked), so k is (apparently) rounded to 0.5. Then, > > depending on how you transform the equation and the exact step at which you > > substitute your value for k, you either get Infinity or 1 (exercise left > > to the reader, or I guess you could just check the stepbystep solution, > > but I haven't). > > > That is how floating point works: you'd rather ideally use > > arbitraryprecision rationals, otherwise, as mentioned already in the > > thread, increase the precision of your floating point numbers. But I do not > > think you can do any of these with Wolfram Alpha. > > > Julio > > You are a fucking clueless monkey Julio, don't you think that > mathematica can handle a simple division, together with Wofram, > mathematica is one of the most__accurate__ math packages out there on > the market. And they should not be able to handle simple floating > point arithmetic that take 3 days to program. Even for me that do not > even claim to be a competent programmer in any language i would do it > in notime. So that is not why....... instead it is their arithmetic > simply fucked up it, so no it isn't sound. They should build it upon > geometrical principles known since Zohan of Babylon. The ones behind > that programming is fucked up prostitutes to mainstream nillywilly > anal imaginary half cats. This is what i think about them. > > http://www.dailymail.co.uk/news/article2321146/WhatearthHalfcatc...http://www.youtube.com/watch?v=1SkUxknvRlc > > http://www.youtube.com/watch?v=ndN_5IrPOhc > Back in the day of Babylon the priest was astronoms, so the whole > geometric priniciples was founded by priests. And the most famous of > them all was Zohan, also known as Zoroaster. The village of Zohan can > still be found in Iran. We often focus upon other traits of > Zoroaster, > that have become larger then life after his death myths, but during > the time of Babylon he was the greatest astronom, mathematician the > world had seen.
What is wrong with your aritmethic?



