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Topic: Matheology � 263
Replies: 57   Last Post: May 17, 2013 8:52 PM

 Messages: [ Previous | Next ]
 Graham Cooper Posts: 4,495 Registered: 5/20/10
Re: Matheology § 263
Posted: May 17, 2013 8:40 PM

On May 18, 10:34 am, Virgil <vir...@ligriv.com> wrote:
> In article
>  Graham Cooper <grahamcoop...@gmail.com> wrote:
>
>
>
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>
>
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>

> > > Cantors does not say that there is no more than one such set, he just
> > > said that there is at least one, and I have provided at least one, in
> > > fact uncountably many of them.

>
> > I want to see the FORMULA
>
> > { n | n ~e f(n) }
>
> > WORK ON
>
> >   f(1) = { 1 , 3 , 6 }
> >   f(2) = { 1 , 5 , 11 }
> >   f(3) = { 2 , 4 , 6 , 8 , 10 }
> >   f(4) = { 4 , 5 , 6 , 7 , 8 }

>
> >   f(n) = N | n>4
>
> > ALL VALUES OF f() ARE SPECIFIED.
>
> > ----------
>
> > Does your favorite Cantors formula
>
> It is not my formula at all, but Cantor's
>
>
>

> > S = { n | n ~e f(n) }
>
> > WORK on the GIVEN f ?
>
> > If it does - WHAT IS S ?

For the given f, ask yourself:

Is 1 in f(1)? YES
Is 2 in f(2)? NO
Is 3 in f(3)? NO
Is 4 in f(4)? YES
Is n in f(n) for n > 4? YES to ALL

> And then work out which will be in { n in |N : ~ n in f(n) }.

I get S = { 2 , 3 }

S = { x | x ~e f(x) }

f(1) = { 1 , 3 , 6 }
f(2) = { 1 , 5 , 11 }
f(3) = { 2 , 4 , 6 , 8 , 10 }
f(4) = { 4 , 5 , 6 , 7 , 8 }
f(n) = N | n>4

You took 5 days and still couldn't calculate Cantors Missing Set.

Herc

Date Subject Author
5/10/13 Virgil
5/13/13 Virgil
5/13/13 Graham Cooper
5/13/13 Virgil
5/13/13 Graham Cooper
5/13/13 Virgil
5/14/13 Graham Cooper
5/14/13 Virgil
5/14/13 Graham Cooper
5/14/13 Virgil
5/14/13 Graham Cooper
5/14/13 Virgil
5/14/13 Graham Cooper
5/14/13 Virgil
5/14/13 Graham Cooper
5/14/13 Virgil
5/15/13 Graham Cooper
5/15/13 Virgil
5/15/13 Graham Cooper
5/15/13 Virgil
5/15/13 Graham Cooper
5/15/13 Virgil
5/15/13 Graham Cooper
5/16/13 Virgil
5/16/13 Graham Cooper
5/16/13 Virgil
5/16/13 Graham Cooper
5/16/13 Virgil
5/16/13 Graham Cooper
5/16/13 Virgil
5/16/13 Graham Cooper
5/16/13 Virgil
5/16/13 Graham Cooper
5/16/13 Virgil
5/16/13 Graham Cooper
5/16/13 Virgil
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5/16/13 Virgil
5/16/13 Graham Cooper
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5/16/13 Graham Cooper
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5/16/13 Virgil
5/16/13 Graham Cooper
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5/17/13 Graham Cooper
5/17/13 Virgil
5/17/13 Graham Cooper
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5/14/13 Virgil