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Topic: Floor of the log equation: s = (floor(log10(x))+1)*x - round((10^(floor(log10(x))+1)-10)/9)
Replies: 4   Last Post: May 22, 2013 11:09 PM

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nepomucenocarlos68@gmail.com

Posts: 1
Registered: 5/19/13
Floor of the log equation: s = (floor(log10(x))+1)*x - round((10^(floor(log10(x))+1)-10)/9)
Posted: May 19, 2013 2:20 PM
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Hi guys! I need your help to solve this equation:

I need to find 'x' for a given 's'. Both of them are natural numbers (>0).

I don't know how to handle the floor term.

[octave/matlab format]
s = (floor(log10(x))+1)*x - round((10^(floor(log10(x))+1)-10)/9);

[or TeX}
s = \left( \lfloor\log(x)\rfloor+1 \right)x - \frac{10^{\lfloor\log(x)\rfloor+1}-10}{9}

[or image]
http://postimg.org/image/r5fd2enll/


Exact or approximate values are good.

Is there a solution? How do I solve it?

Are there any methods to search & find a solution?

Regards,

Carlos



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