Daniel
Posts:
58
Registered:
7/24/12


Re: Average the same elements of the list
Posted:
May 24, 2013 5:24 AM


data={{{a1,b1,c1},d1},{{a2,b2,c2},d2}}; {#[[1, 1]], #[[All, 2]] // Mean} & /@ SplitBy[data, First]
output: {{{a1, b1, c1}, d1}, {{a2, b2, c2}, d2}}
data={{{a1,b1,c1},d1},{{a1,b1,c1},d2}}; {#[[1, 1]], #[[All, 2]] // Mean} & /@ SplitBy[data, First]
output: {{{a1, b1, c1}, (d1 + d2)/2}}
> Hello, > I have list which is something like > data={ > {{a1,b1,c1},d1},{{a2,b2,c2},d2}} > I would like to get new list which gets average of > the second elements if the first elements in the > sublists are all the same. > Namely if a1=a2,b1=b2,c1=c2 > new list would look like > datanew={{a1,b1,c1},Mean[{d1,d2}] > Is there an elegant way to do this ? > Thanks! >

