Jon Morris
Posts:
8
From:
Berlin
Registered:
3/4/10
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Re: Map
Posted:
May 25, 2013 5:34 AM
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Explanation received via email reposted incase it helps other people:
hklist = Array[h, {5, 3}];
bragg = {b1, b2, b3};
qbarlist = Map[(# - bragg) &, hklist, {2, 2}];
As stated in the documentation ( http://reference.wolfram.com/mathematica/ref/Map.html ), the third argument to Map is the level specification and the form {n1, n2} specifies levels n1 through n2. In this case n1 and n2 are equal so it is equivalent to just {n1}.
qbarlist === Map[(# - bragg) &, hklist, {2}]
True
If you look at your outputs carefully you will see that you do not get the same result with a third argument of {1}
qbarlist === Map[(# - bragg) &, hklist, {1}]
False
qbarlist // Dimensions
{5, 3, 3}
Map[(# - bragg) &, hklist, {1}] // Dimensions
{5, 3}
Examine the two different arrays above to understand the different behavior.
Bob
Reply:
What I was hoping it would give as a result was:
{{h[1,1]-b1, h[1,2]-b2, h[1,3]-b3},
{h[2,1]-b1, h[2,2]-b2, h[2,3]-b3},
{h[3,1]-b1, h[3,2]-b2, h[3,3]-b3},...
After your explanation I realise that I get that result with Map[(#-bragg) &, hkllist, {1}] and this makes me think that this may have given a bug in the original code.
Thanks for your help!
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