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Re: Through[Divide[f1, f2][x]]
Posted:
May 27, 2013 4:20 AM


On 26 May 2013, at 11:06, Ray Koopman <koopman@sfu.ca> wrote:
> Either of these will give you f1[x]/f2[x]: > > Divide@@{f1@#,f2@#}&@x > > Divide@@(#@x&)/@{f1,f2} > > Sometimes it would be nice to have a "reverse map", that > applied each of a list of functions to a single argument, > instead of a single function to each of a list of arguments.
I am not sure I understand what you mean. Why doesn't Through do that?
Through[{f, g, h}[x]]
{f[x], g[x], h[x]}
Andrzej Kozlowski



