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Topic: Through[Divide[f1, f2][x]]
Replies: 3   Last Post: May 28, 2013 3:48 AM

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Andrzej Kozlowski

Posts: 226
Registered: 1/29/05
Re: Through[Divide[f1, f2][x]]
Posted: May 27, 2013 4:20 AM
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On 26 May 2013, at 11:06, Ray Koopman <> wrote:

> Either of these will give you f1[x]/f2[x]:
> Divide@@{f1@#,f2@#}&@x
> Divide@@(#@x&)/@{f1,f2}
> Sometimes it would be nice to have a "reverse map", that
> applied each of a list of functions to a single argument,
> instead of a single function to each of a list of arguments.

I am not sure I understand what you mean. Why doesn't Through do that?

Through[{f, g, h}[x]]

{f[x], g[x], h[x]}

Andrzej Kozlowski

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