>> >> What value of 't' you think will make exp(sin(t)) zero? >> sin(t) is between -1 and +1. So, just plot exp() between these >> 2 values and you'll see it is not zero. >> >> You have to go to -infinity and beyond to have any luck of >> making exp() in the limit go to zero. >> >> --Nasser
> > I am using the solve function to solve the equation ft for t > > clc, clear; > syms t ft > ft = exp(sin(t)); > solve(ft,t) > > However, the result of this ^^^ is as follows: > > Warning: Explicit solution could not be found. >> In solve at 179 > ans = > [ empty sym ] > > I don't want to solve the equation for a value, but a variable. >I want the equation t with respect to ft. Is this any clearer now? >
Thank you so much, yes, much more clear now.
But the answer is still the same I am afraid. Please re-read what I wrote earlier.
There is no solution to exp(sin(t))=0, in other words, there is no 't' which will make exp(sin(t)) zero.
Did you try to plot exp(x) for x=-1..1 ? did you see exp(x) cross the x-axis anywhere? It does not. So there is no solution, it is never zero.