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Topic: Need Help!! please
Replies: 1   Last Post: Jul 3, 2013 10:41 PM

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Posts: 132
Registered: 11/27/12
Re: Need Help!! please
Posted: Jul 3, 2013 10:41 PM
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If there exist x such that x^1/log(x)= 5 then that same x satisfies x= 5^log(x).

It is easy to see that that last equation is satisfied by x= 1. It is also easy to see that if 0< x< 1, x< 5^log(x)and if x> 1, x> 5^log(x) so that 1 is the ONLY x for which x= 5^log(x). But then log(x)= log(1)= 0 so 1/log(1) does not exist.

Date Subject Author
Read Need Help!! please
Katy rose
Read Re: Need Help!! please

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