Search All of the Math Forum:
Views expressed in these public forums are not endorsed by
NCTM or The Math Forum.


grei
Posts:
132
Registered:
11/27/12


Re: Need Help!! please
Posted:
Jul 3, 2013 10:41 PM


If there exist x such that x^1/log(x)= 5 then that same x satisfies x= 5^log(x).
It is easy to see that that last equation is satisfied by x= 1. It is also easy to see that if 0< x< 1, x< 5^log(x)and if x> 1, x> 5^log(x) so that 1 is the ONLY x for which x= 5^log(x). But then log(x)= log(1)= 0 so 1/log(1) does not exist.



