
Re: How do i go on finding the cordinate of the middle of hypotenuse of a right angled triangle?
Posted:
Jul 20, 2013 9:13 AM


jonas.thornvall@gmail.com <jonas.thornvall@gmail.com> wrote: > Den lördagen den 20:e juli 2013 kl. 04:30:06 UTC+2 skrev William > Elliot: >> On Fri, 19 Jul 2013, jonas.thornvall@gmail.com wrote: >> >>> Using a cartesian dot base cordinate system.(computer graphics) >> >>> I have right sided triangles at differents slopes, and need to find the >>> hypotenuse middle cordinate of them, how do i go on to do that? >>> >> >> I presume you mean the midpoint of hypothenuse. >> >> Assuming you know the coordinates of the three points of the >> triangle, >> ABC with the right angle at C, average the coordinates of A and B. >> >>> Can it be done without trigonometry? >> >> Yes, if A = (a,b) and B = (r,s), then the mid point >> of the line segement AB is ((a + b)/2, (r + s)/2)) > > I do not know what i was thinking of course it is obvious that the > line form a rectangle regardless slope. Thanks you set my neuron into > a straight path again Elliot. I was all triangulated for a while ;D
Perhaps William Elliot was triangulated for a while too, since, if A = (a,b) and B = (r,s), then the mid point AB is actually ( (a+r)/2, (b+s)/2) ) ;)
Dirk Vdm

