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Topic: Calculating Pi using polygon sides sum / radius
Replies: 40   Last Post: Aug 2, 2013 5:27 PM

 Messages: [ Previous | Next ]
 JT Posts: 1,448 Registered: 4/7/12
Re: Calculating Pi using polygon sides sum / radius
Posted: Jul 30, 2013 9:33 AM

Den tisdagen den 30:e juli 2013 kl. 12:27:56 UTC+2 skrev Peter Percival:
> jonas.thornvall@gmail.com wrote:
>

> > Den tisdagen den 30:e juli 2013 kl. 11:58:10 UTC+2 skrev jonas.t...@gmail.com:
>
> >> If you create a hexagon with the radius of one, and recursively double the number of vertices of the hexagon(have same radius as side length)
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> >>
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> >>
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> >>
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> >> I guess the sum of side lengths/radius close in on Pi infinitly, so i imagine that that they will indeed come closer as you double up the vertices recursively. But is there a digit there they won't be the same regardless the number of digits.
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> >>
>
> >>
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> >>
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> >> Maybe this is a valid way to calculate Pi?
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>
>
> With the correction, yes. Archimedes used it.
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>
>

> >
>
> > Side lengths/ diameter it should be... sorry
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> >
>
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>
>
> --
>
> Nam Nguyen in sci.logic in the thread 'Q on incompleteness proof'
>
> on 16/07/2013 at 02:16: "there can be such a group where informally
>
> it's impossible to know the truth value of the abelian expression
>
> Axy[x + y = y + x]".

Am i correct assuming that using a hexagon is the prefered way with archimedes technique, and i set the radius to one. So 2*r*x=perimeter.

Date Subject Author
7/30/13 JT
7/30/13 JT
7/30/13 Peter Percival
7/30/13 JT
7/30/13 Richard Tobin
7/30/13 JT
7/30/13 Peter Percival
7/30/13 JT
7/30/13 JT
7/30/13 JT
7/30/13 JT
7/31/13 William Elliot
7/31/13 JT
7/31/13 Peter Percival
7/31/13 William Elliot
8/1/13 JT
8/1/13 JT
8/1/13 Virgil
8/1/13 Virgil
8/1/13 JT
8/1/13 JT
8/1/13 Virgil
8/1/13 JT
8/1/13 Virgil
8/1/13 Virgil
8/1/13 Shmuel (Seymour J.) Metz
8/1/13 Virgil
8/2/13 JT
8/2/13 JT
8/2/13 Virgil
8/2/13 JT
8/2/13 Virgil
8/2/13 Brian Q. Hutchings
8/2/13 Brian Q. Hutchings
8/2/13 Virgil
8/2/13 JT
8/2/13 Shmuel (Seymour J.) Metz
8/1/13 JT
8/1/13 Virgil
8/1/13 JT
8/1/13 Virgil