"Torsten" wrote in message <firstname.lastname@example.org>... > "Sanaa" wrote in message <email@example.com>... > > "Torsten" wrote in message <firstname.lastname@example.org>... > > > "Sanaa" wrote in message <email@example.com>... > > > > Hi all, > > > > How to integrate a function within a loop and the limits of integration are variables? > > > > For instance, y(i)*(1-y(i)) is the function I wish to integrate from 0.25*i to t where > > > > t \in (0.25*i, 0.25*(i+1)). > > > > Any help is really appreciated. > > > > Sanaa Moussa > > > > > > I think y(i)*(1-y(i)) is just a real number, not a function, isn't it ? > > > > > > Best wishes > > > Torsten. > > > > Thanks for replying. You are right, but I mean the function is y*(1-y) which I want to put it into a loop > > My code is > > itermax=300;min=itermax-9;% That is we plot from 291:300 i.e. 10 values of x only. > > r=0.25; > > for rho=0:0.001:4 > > %x0=0.1; > > x(1)=0.1; > > for i=1:itermax-1 > > %t=linspace(i*r,(i+1)*r,itermax) > > y(i+1)=x(i); > > x(i+1)=x(i)+ rho*int(y(i)*(1-y(i)),i*r,(i+1)*r); > > end > > %fix(y) > > plot(rho*ones(10),x(min:itermax),'b.','linewidth',0.1) > > hold on > > end > > fsize=15; > > xlabel('\rho','FontSize',fsize) > > ylabel('\itx','FontSize',fsize) > > %title('r=0.25, \alpha=1','FontSize',fsize) > > hold off > > % print(gcf, '-djpeg', '-zbuffer', 'bif.png'); > > > > I get the error > > Function 'int' is not defined for values of class 'double'. > > what does this mean and how to fix it please? > > Many thanks in advance. > > It means what I said before: > y(i)*(1-y(i)) > is a scalar value and not a function. > So "int" does not know how to handle this because it expects a function, not a scalar as its first input argument. > > Best wishes > Torsten.
Sorry for not posing my question correctly. The function I want to integrate is y(s)*(1-y(s)) ds from (n*0.25) to t, and t/in(n*0.25, (n+1)*0.25). Do you have any idea on how to format my code above to solve my problem? Thanks a lot in advance