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Re: powering is cube shaped
Posted:
Aug 1, 2013 11:39 PM



On Thu, Aug 1, 2013 at 2:19 PM, frank zubek <fzubek@yahoo.com> wrote:
> Kirby wrote; > That's why she says "square root of 2 cubed" because the model of 3rd > powering is cube shaped. >   > So sqr2 cubed = 2.828427125/1.060660172=3 >
I wouldn't say that. sqr2 "cubed" is sqr2 x sqr2 x sqr2.
Anything "cubed" is times itself once (2 x 2) then again (2 x 2) x 2.
The multiplication operator is applied twice.
Note that we have notions of powering in mathematics that are not geometrically represented.
Permutations may be powered, hundreds of times, before they come back to their original selves. They go into orbit.
RSA works on this principle:
a) raise m (plaintext message) to some power e modulo N to get c (ciphertext)
b) then raise c to power e * d mod N and you're pack to message m.
From OSCON last week, this picture, a slide from a talk on Discrete Math from a sector of the economy that goes begging to fill its vacancies:
http://www.flickr.com/photos/kirbyurner/9360962237/
Does your high school teach about RSA? If not, consider writing to the governor of your state etc. etc.
They teach it at Phillips Academy (a good school). The software is free. So what's the hold up? Every web browser uses it. Isn't "how things work" important to high schools any more?
> So 2 cubed = 8 x .375 = 3 > >
Not in my book. Not sure what you're smoking.
> So you use a constant to arrive at cube = 3 > I use a constant to also arrive at cube = 3 > >
I use the fact that a unit volume tetrahedron is inscribed in a cube three times its size.
How that tetrahedron got to be unit in the first place is what you're missing.
You never learned you had an option in the 3rd grade or even the 6th grade, or even the 16th grade.
Do professors even know?
If they're competent doctors of philosophy they do, by which I don't mean "Ph. D" (most of those are deeply specialized and can't be expected to know).
Dr. Loeb knew. He was writing about this stuff in the 1960s.
> So 1.060660172/.375 = 2.828427125 > > ALL THIS IS A NONSESE, a number shuffle. >
For you it is, and coming from you it is, yes. You need to comprehend before it makes sense.
> Tetrahedron is NOT cube shaped yet we using thir powering. vol. of a > sphere is not cube shape yet we use r cubed times Pi/4 > > You don't have to be cubeshaped to represent a 3rd power.
Lets go back to the case of simple triangles:
Here's a picture of 4 x 4 (why would you say "four squared" looking at this picture?):
http://wpc.puzzles.com/history/tests/2000wpc/images/triangles1.gif
Count the number of triangles: 16. 4 x 4 = 16.
What's a picture of 3 x 3 x 3? Most people hold up a picture of a cube, 3 on each side.
But the 3frequency tetrahedron made of four balls along each edge, subdivides into an IVM, a scaffolding, of smaller tetrahedra and octahedra. If you add up those volumes (no holes) you get 27. Tetrahedron = 1. Octahedron = 4. Together, these fill all space.
That's starting with a tetrahedron of unit / 1.
http://www.rwgrayprojects.com/synergetics/s09/figs/f9001.html
Same IDENTICAL cubes have SAME volumes period. > > frank >
Says who? You? You forbid me to develop along this other branch of mathematics? By what reasoning, if any?
How many Xs? XXXXX XXXXX XXXXX
Some say "15" but that's in base 10. Did we have to use base 10? In Base 7, their number is "21".
When I multiply 3 x 3 x 3, I have a choice as to which language game I want to work in. I've got the XYZ channel and the IVM channel. In the former, I see a cube of volume 27, in the latter I see a tetrahedron of volume 27.
Kirby



