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Topic: PDE - spherical coordinates question (polar)
Replies: 2   Last Post: Aug 21, 2013 1:14 PM

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Torsten

Posts: 1,457
Registered: 11/8/10
Re: PDE - spherical coordinates question (polar)
Posted: Aug 21, 2013 2:46 AM
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"Saad" wrote in message <kuvtva$guv$1@newscl01ah.mathworks.com>...
> Hi,
> I'm trying to solve the following PDE using (pdepe).
> Does anyone have any tips on how to input the variable coefficients for this equation.
>
> dH/dt + 1/sinx d/dx(H^3 (sinx)^2)=0
>
>
> Thanks,
> Saad


pdepe is suited for PDEs which contain a second-order spatial derivative (in your case, this would be an expression involving d^2H/dx^2).
Since your equation is a first-order PDE, you will have to solve it using a different tool.
Differentiating out, you get
dH/dt + 3*H^2*sin(x)*dH/dx = -2*H^3*cos(x).

Best wishes
Torsten.



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