dpb
Posts:
8,982
Registered:
6/7/07


Re: Combine string matrix and integer matrix
Posted:
Aug 24, 2013 12:49 AM


On 8/23/2013 10:45 PM, Sincloe Brans wrote: > dpb <none@non.net> wrote in message <kv8s2n$a81$1@speranza.aioe.org>... ...
>> You _can't_ concatenate different types into the same array. >> >> You _can_ make C a cell array w/ a numeric and a character array in >> the cells. >> >> Or, you can convert all the numeric values to strings and create a >> larger character arraya cell array would probably be more handy. >> >> What is the end result of this desired operation, pray tell? If you >> were describe what your actual objective is in the end instead of how >> to do what is essentially impossible a better solution may ensue. >> ...
> My end result should be e.g. > C= [A B] = 1 3 4 4 a b c > 3 3 4 5 a a a > 4 4 5 5 a c a > 5 4 4 5 a b c > > Converting all to any one type is totally fine. > I used 'cellstr' to convert the B matrix and then I combined using cell > array, > C = [num2cell(A) cellstr (B)] > > when I do this way i see the strings with ' ' in each cell which is hard > if I want to save in excel and do some calculations. > My final matrix should have no 'a', just a (as shown in C matrix). Not > sure if it is possible in matlab, if not I can live with this. > Thank you so much for your time and helping!
>> B = {'a b c'; 'a a a'; 'a c a'; 'a b c' }; >> A = [1 3 4 4; 3 3 4 5; 4 4 5 5; 5 4 4 5]; >> c=[num2str(A) repmat(' ',size(A,1),1) char(B)] c = 1 3 4 4 a b c 3 3 4 5 a a a 4 4 5 5 a c a 5 4 4 5 a b c >>
Looks good, doesn't it? Looks can be deceiving on the other end, however...
NB
>> c=[num2str(A) repmat(' ',size(A,1),1) char(B)] c = 1 3 4 4 a b c 3 3 4 5 a a a 4 4 5 5 a c a 5 4 4 5 a b c >> c(1) ans = 1
Returns only the first character in the character arrayto get the string you would have to use the full subscripting
>> c(1,:) ans = 1 3 4 4 a b c >>
OTOH, if you make a cell array,
>> c={[num2str(A) repmat(' ',size(A,1),1) char(B)]} c = [4x16 char] >> c(1) ans = [4x16 char]
Not what you wanted, you have to dereference the cell content w/ the {} curly braces instead of parens...
>> c{:} ans = 1 3 4 4 a b c 3 3 4 5 a a a 4 4 5 5 a c a 5 4 4 5 a b c >> c{1} ans = 1 3 4 4 a b c 3 3 4 5 a a a 4 4 5 5 a c a 5 4 4 5 a b c >>


