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Re: The integration test suites for Sage.
Posted:
Sep 6, 2013 12:52 PM


peter.luschny@gmail.com schrieb: > > M> Your numbers 21, 23, 49 are shown as done while Albert's are not. > M> And your number 43 is shown as wrong whereas Albert records > M> a success. > > Albert used Maxima 5.28 whereas I used Sage 5.10. I do not know which > Maxima version Sage 5.10 uses. They might be different. >
The Maxima integrator would be undergoing noticeable development then. A pleasant surprise.
> So let's check by the output given on my page: > > Charlwood_problem(43) > integrand : tan(x)/sqrt(tan(x)^4 + 1) > antideriv : 1/4*sqrt(2)*arctanh(1/2*(tan(x)^2  1)*sqrt(2)/ sqrt(tan(x)^4 + 1)) > maxima : 1/4*sqrt(2)*arcsinh(2*sin(x)^2  1) > > Looks like 'antideriv'  'solution' = 0. Is this ok? > Thus 43 is indeed a success. Wouldn't Maxima's result in this > case not be the 'better' antiderivative for Albert's "Book"?
Hum. Plotting the antiderivatives along the real axis reveals that Sage/Maxima got the overall sign wrong while Albert got it right. After sign inversion the Maxima result appears to be correct on the real axis. But the ATANH antiderivative holds on the entire complex plane, while the (corrected) ASINH result doesn't: with the Derive definition ASINH(z) = #i*ASIN(#i*z) = LN(SQRT(1+z^2)z), it differentiates back to a function that differs from the integrand in large parts of the plane. But then Maxima doesn't claim to deliver antiderivatives for the entire complex plane, or does it?
Anyway, number 43 must be counted as a failure.
> > Charlwood_problem(21) > integrand : x^3*arcsin(x)/sqrt(x^4 + 1) > antideriv : 1/4*sqrt(x^2 + 1)*x  1/2*sqrt(x^4 + 1)*arcsin(x) + 1/4*arcsinh(x) > maxima : 1/4*sqrt(x^2 + 1)*x  1/2*sqrt(x^4 + 1)*arcsin(x) + 1/4*arcsinh(x) > > That's easy to judge.
Yes, they are identical. Perhaps Albert made a mistake here?
> > Charlwood_problem(23) > integrand : x*log(x + sqrt(x^2 + 1))*arctan(x)/sqrt(x^2 + 1) > antideriv : sqrt(x^2 + 1)*log(x + sqrt(x^2 + 1))*arctan(x)  x*arctan(x)  1/2*log(x + sqrt(x^2 + 1))^2 + 1/2*log(x^2 + 1) > maxima : (sqrt(x^2 + 1)*log(x + sqrt(x^2 + 1))  x)*arctan(x) + 1/2*log(x + sqrt(x^2 + 1))^2  log(x + sqrt(x^2 + 1))*arcsinh(x) + 1/2*log(x^2 + 1) > > What did I overlook?
Apparently nothing. On Derive, for complex x and with some manual assistance, the Sage/Maxima result differentiates back to
x*ATAN(x)*LN(SQRT(x^2 + 1) + x)/SQRT(x^2 + 1) + (LN(SQRT(x^2 + 1)  x) + LN(SQRT(x^2 + 1) + x))/SQRT(x^2 + 1)
and the second term vanishes identically over the complex plane. So number 23 must be counted as a full success. Perhaps Albert made a mistake here too?
> > Charlwood_problem(49) > integrand : arcsin(x/sqrt(x^2 + 1)) > antideriv : x*arcsin(x/sqrt(x^2 + 1)) + arctan(sqrt(2*x^2 + 1)) > maxima : x*arcsin(x/sqrt(x^2 + 1))  1/2*(2*I*x^2 + I)/ sqrt(2*x^2  1)  1/2*I*sqrt(2*x^2  1)  1/2*I*log(sqrt(2*x^2  1)  1) + 1/2*I*log(sqrt(2*x^2  1) + 1) > > Maxima uses 'I' here. I think Albert rates this as an error. And he > is right. Charlwood demanded only real solutions, if I remember right. > So I will classify this as deficient.
The Sage/Maxima result is more than just deficient: it is incorrect for 1/SQRT(2) < x < 1/SQRT(2) on the real axis. For complex x and with some manual assistance on Derive it differentiates back to
ASIN(x/SQRT(1  x^2)) + x/(1  x^2)*(1/SQRT(1  2*x^2) + #i/SQRT(2*x^2  1))
and the second term does not vanish here; it is nonzero in two entire quadrants of the complex plane. So Albert got this one right, and number 49 must indeed be counted as a failure.
Martin.



