
Re: Leaving 0^0 undefined  A numbertheoretic rationale
Posted:
Sep 12, 2013 12:26 AM


On Wednesday, September 11, 2013 5:09:52 PM UTC4, Peter Percival wrote: > Dan Christensen wrote: > > > > > > > > Show me a contradiction that arises from 0^0 = 0. > > > > The product of the empty set is 1, hence 0^0 = 1. That contradicts 0^0 > > = 0. Therefore 0^0 doesn't = 0. >
You are talking about some other settheoretic notion of exponentiation, not the usual arithmetic operator that we are discussing here.
More convincing would be obtaining a contradiction by assuming only 0^0=0 along with the usual rules of naturalnumber arithmetic, including the usual Laws of Exponents.
Dan Download my DC Proof 2.0 software at http://www.dcproof.com

