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Topic: The first new theorem Primes
Replies: 3   Last Post: Sep 19, 2013 4:11 AM

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Brian Q. Hutchings

Posts: 6,148
Registered: 12/6/04
Re: The first new theorem Primes
Posted: Sep 18, 2013 12:24 PM
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can you state your premise succinctly, dood

> Since A2 = 1000000A1
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> A2- A1 = 999999A1
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> Then
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> Q2(B) - Q1(B) = 999999A1
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> Dividing through by B, we obtain.
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> Eqtn. (3a) Q2 - Q1 = ( 999999A1)/B
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> 11235053 - 11 = (999999)(13718)/1221
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> 11235042 = 11235042
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> We have an integer value on the left hand side of Eqtn. (3a), and thus we
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> should also have an integer value on the right hand side of Eqtn. (3a). In
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> order for this to be true, since A and B have no prime factor in common,
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> then 999999 must be evenly divisible by B .
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> Checking this out in the numerical example, we find.
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> 999999/1221 = 819
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> An integer quotient value is produced.
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> Thus we have shown that our randomly chosen odd integer, 1221, is a factor
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> of 999999.





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