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Topic: Is (t^2-9)/(t-3) defined at t=3?
Replies: 166   Last Post: Oct 30, 2013 9:41 AM

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Robin Chapman

Posts: 258
Registered: 5/29/08
Re: Is (t^2-9)/(t-3) defined at t=3?
Posted: Sep 30, 2013 4:03 AM
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On 30/09/2013 07:58, Ciekaw wrote:
> On Saturday, September 28, 2013 6:30:42 PM UTC+2, Hetware wrote:
> >
>> But F(t) is not defined at t=3 because it evaluates to 0/0.
>>

>
> Hint L'Hôpital's rule
>
> f(t)=t-3
> f'(t)=1
>
> lim[f(t)/f(t)]=lim[f'(t)/f'(t)]=lim[1/1]=1
>
>
> Analogy:
> If x=0 then sin(x)/x = 1


Hetware: 0/0 = 3

Ciekaw: 0/0 = 1

Any more entrants?



Date Subject Author
9/28/13
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Hetware
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Michael F. Stemper
9/28/13
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Hetware
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Peter Percival
9/29/13
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quasi
9/28/13
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Hetware
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Richard Tobin
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Hetware
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9/29/13
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Hetware
10/6/13
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Hetware
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Hetware
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10/7/13
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9/29/13
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9/29/13
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magidin@math.berkeley.edu
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Hetware
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LudovicoVan
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10/12/13
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10/13/13
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Richard Tobin
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9/29/13
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10/13/13
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10/14/13
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10/16/13
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10/16/13
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10/19/13
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10/19/13
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10/19/13
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Hetware
10/20/13
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Hetware
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Richard Tobin
10/20/13
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Hetware
10/30/13
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10/19/13
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10/10/13
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Ronald Benedik
10/10/13
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Peter Percival
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Virgil
10/18/13
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Hetware
10/19/13
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Peter Percival
10/19/13
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fom
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Peter Percival
10/19/13
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Hetware
10/19/13
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Peter Percival
10/19/13
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Hetware
10/19/13
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fom
10/19/13
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magidin@math.berkeley.edu
10/19/13
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Hetware
10/19/13
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magidin@math.berkeley.edu
10/20/13
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Hetware
10/20/13
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quasi
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Peter Percival
10/20/13
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magidin@math.berkeley.edu
10/20/13
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Hetware
10/20/13
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Arturo Magidin
10/20/13
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10/19/13
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