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Topic: Is (t^2-9)/(t-3) defined at t=3?
Replies: 166   Last Post: Oct 30, 2013 9:41 AM

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Peter Percival

Posts: 945
Registered: 10/25/10
Re: Is (t^2-9)/(t-3) defined at t=3?
Posted: Oct 6, 2013 11:45 AM
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Hetware wrote:

> OK. I turned this around and can see the problem. I was assuming f(t)=
> (t^2-9)/(t-3) is continuous, which is not justified from the context. At
> t=3, x can be anything in t^2 - 9 = x (t - 3).


If f is a function with domain the most inclusive set of reals possible,
then f is continuous.

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9/28/13
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Peter Percival
9/29/13
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Hetware
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Richard Tobin
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Hetware
10/6/13
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Hetware
10/6/13
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Peter Percival
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Hetware
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magidin@math.berkeley.edu
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10/13/13
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10/16/13
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10/19/13
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10/19/13
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10/20/13
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10/10/13
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Peter Percival
10/10/13
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Virgil
10/18/13
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Hetware
10/19/13
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Peter Percival
10/19/13
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fom
10/19/13
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Peter Percival
10/19/13
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Hetware
10/19/13
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Peter Percival
10/19/13
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Hetware
10/19/13
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fom
10/19/13
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magidin@math.berkeley.edu
10/19/13
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Hetware
10/19/13
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magidin@math.berkeley.edu
10/20/13
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Hetware
10/20/13
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Peter Percival
10/20/13
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10/20/13
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10/20/13
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10/19/13
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