> > I now understand what I was missing. If I assume f(t) = (t^2-9)/(t-3) > is continuous at t=3,
Since a function can't be continuous at a point not in its domain, that is an unwise assumption. What is the case is that there is a function defined on the real numbers which agrees with f where f is defined and has a value at 3 and it continuous.
> then it is defined there. In just about > everything I do, functions are assumed to be continuous unless there is > some obvious coordinate, or manifold singularity. It took me a while to > get the assumption of continuity out of my head.
-- The world will little note, nor long remember what we say here Lincoln at Gettysburg