> > Let f(t) = (t^2-9)/(t-3) where t!=3, and f(3) = limit[(t^2-9)/(t-3), > t->3]. Is, by this definition, f(t) a continuous function over the set > of real numbers t?
Yes.
> For the sake of further exposition, I will answer for > you in the affirmative.
You know, don't you, that the f you have now defined is not the f you wrote about previously?
-- The world will little note, nor long remember what we say here Lincoln at Gettysburg
