On Sunday, October 20, 2013 6:01:39 PM UTC-4, Bart Goddard wrote: > Dan Christensen <Dan_Christensen@sympatico.ca> wrote in > > news:email@example.com: > > > > > > > Whether there are two possibilities or ten or an infinite number, the > > > end result is the same. > > > > No, it's not. If one defines 0^0 = 0 or 0^0 = 1, then > > the exponent laws work.
That is not the basis of a formal definition. Let's see YOUR definition. You don't seem to like mine:
1. ^: NxN -> N 2. x^0 = 1 for x=/=0 3. x^(y+1) = x^y * x