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Topic: Let Z be a complex number. How do you (elegantly) prove that |z - 1|
> 2 implies |z^3 - 1| > 1

Replies: 11   Last Post: Oct 29, 2013 2:49 AM

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 William Elliot Posts: 2,634 Registered: 1/8/12
Re: Let Z be a complex number.
Posted: Oct 27, 2013 9:07 PM

On Sun, 27 Oct 2013, dan.ms.chaos@gmail.com wrote:

> > Are you sure of "> 2"?
>
> sqr((x + 1)^2 + y^2) > 2 can be rewritten as
> ((x + 1)^2 + y^2) > 4 , <=>
> x^2 + 2x + 1 +y^2 > 4 <=>
> x^2 +2x + y^2 > 3 which is what we've started with.
> The same goes for the other relation.

What happen to the problem statement?
It disappeared and with it's disappearance, poof, no problem!

Date Subject Author
10/25/13 dan.ms.chaos@gmail.com
10/25/13 William Elliot
10/26/13 dan.ms.chaos@gmail.com
10/27/13 William Elliot
10/27/13 dan.ms.chaos@gmail.com
10/27/13 William Elliot
10/28/13 dan.ms.chaos@gmail.com
10/28/13 William Elliot
10/28/13 Roland Franzius
10/26/13 David C. Ullrich
10/28/13 Rock Brentwood
10/29/13 dan.ms.chaos@gmail.com