On Saturday, November 2, 2013 8:57:52 AM UTC-4, Bart Goddard wrote: > Dan Christensen <Dan_Christensen@sympatico.ca> wrote in > > news:firstname.lastname@example.org: > > > > >> The point, as I've said repeatedly, is that your > > >> "theorem" assumes that it has a value. If it's not > > >> defined, then it has no value (or meaning.) > > > > > > > > > 0^0 is undefined in the same sense that the number x is undefined in > > > 0*x = 0. Any value works in both cases. > > > > That's hardly "undefined." Maybe "indeterminate" is what > > you're looking for.
In practice, it amounts to the same thing: You can't assume that 0^0 has any particular value -- not 1 or 0 or any other number. Deal with it, Barty.