
Re: Simplifying Algebraic Expressions with Subtracted Expressions
Posted:
Nov 14, 2013 2:19 PM


R Hansen sasy (white space condensed): >The Ma problem works the same way, through literal substitution... 3/5 {morning batch) minus 1/4(13/5) {evening batch} < This is the literal interpretation of what was written. equal 200
Yes, I see that, but is that not, (more explicitly): [1] (3/5)x  (1/4(13/5)x) = 200 ?
Not exactly the same starting point, and the x really is there, done that way. Has to be.
More explictly, the Ma version would be: [2] x = 200 % (3/5  1/4(13/5))
But since the x is already isolated, I will grant the point that this is "arithmetic". But, although one can sweep that little first step that leads from [1 expression to Ma's under the rug of "done in the head", I think that would be a cheat.
Cheers, Joe N Cheers, Joe N

