
Re: Simplifying Algebraic Expressions with Subtracted Expressions
Posted:
Nov 14, 2013 4:56 PM


R Hansen says: >The trick is reading the Ma problem directly into the coefficient (3/5  1/4(13/5)) in one pass
I'm not arguing that your interpretations are not just fine  I just wonder if that's what she meant. She seems to be saying there is no manipulation of "the unknown quantity" (x) in an algebraic fashion, either mentally or on paper. I'm skeptical.
The closest I can think of would be to set it up as a proportion type problem right away:
x / 200 = 1 / (3/5  1/4(13/5))
(Which is similar to your idea, I think.)
Cheers, Joe N

