LudovicoVan
Posts:
3,569
From:
London
Registered:
2/8/08


Re: Formal proof of the ambiguity of 0^0
Posted:
Nov 17, 2013 12:14 PM


"Dan Christensen" <Dan_Christensen@sympatico.ca> wrote in message news:05b0baba558f4c1980f2f627dbd1b441@googlegroups.com... > On Sunday, November 17, 2013 10:19:33 AM UTC5, Julio Di Egidio wrote: <snip> >> We were simply explained that 0^0 = 0/0, because x^0 = x/x when extending >> the notion of repeated multiplication to nonpositive exponents. > > I can see the reasoning behind it, but I don't like the idea setting two > undefined expressions equal to one another.
Nobody is setting two undefined expressions *equal* to one another, I was speaking informally. Regardless, you quote elementary algebra books, so not addressing objections.
Julio

