LudovicoVan
Posts:
4,110
From:
London
Registered:
2/8/08
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Re: Formal proof of the ambiguity of 0^0
Posted:
Nov 17, 2013 12:14 PM
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"Dan Christensen" <Dan_Christensen@sympatico.ca> wrote in message
news:05b0baba-558f-4c19-80f2-f627dbd1b441@googlegroups.com...
> On Sunday, November 17, 2013 10:19:33 AM UTC-5, Julio Di Egidio wrote:
<snip>
>> We were simply explained that 0^0 = 0/0, because x^0 = x/x when extending
>> the notion of repeated multiplication to non-positive exponents.
>
> I can see the reasoning behind it, but I don't like the idea setting two
> undefined expressions equal to one another.
Nobody is setting two undefined expressions *equal* to one another, I was
speaking informally. Regardless, you quote elementary algebra books, so not
addressing objections.
Julio
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